5. VECTOR ALGEBRA

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5. VECTOR ALGEBRA


5.1 Definition, Notation, and Rectangular Resolution of a Vector

What is a Vector?

A vector is a mathematical quantity that has both magnitude and direction. It is typically represented as an arrow, where the length of the arrow represents the magnitude, and the direction of the arrow indicates the direction of the vector.

Notation: Vectors are usually denoted by boldface letters, such as A, B, or A\vec{A} (when written in regular text).

Representation of a Vector:

In a two-dimensional space, a vector A\vec{A} can be represented by an ordered pair (Ax,Ay)(A_x, A_y), where:

  • AxA_x is the x-component of the vector (horizontal component).
  • AyA_y is the y-component of the vector (vertical component).

In three-dimensional space, a vector A\vec{A} is represented as (Ax,Ay,Az)(A_x, A_y, A_z), where AzA_z is the z-component (third dimension).

For example, a vector A\vec{A} in 2D may be written as:

A=Axi^+Ayj^\vec{A} = A_x \hat{i} + A_y \hat{j}

where i^\hat{i} and j^\hat{j} are the unit vectors along the xx-axis and yy-axis, respectively.

Rectangular Resolution of a Vector:

The process of resolving a vector into its components along the coordinate axes (typically the xx, yy, and zz-axes in 3D space) is called rectangular resolution.

For a vector A\vec{A}, if the magnitude is AA and the angle with the xx-axis is θ\theta, the components of the vector in terms of the unit vectors i^\hat{i} and j^\hat{j} (in 2D) are:

Ax=Acosθ,Ay=AsinθA_x = A \cos \theta, \quad A_y = A \sin \theta

In 3D, the vector A\vec{A} can be resolved as:

A=Axi^+Ayj^+Azk^\vec{A} = A_x \hat{i} + A_y \hat{j} + A_z \hat{k}

where AxA_x, AyA_y, and AzA_z are the components of the vector along the xx, yy, and zz-axes, respectively.

Example:

If a vector A\vec{A} has a magnitude of 5 units and makes an angle of 3030^\circ with the xx-axis in a 2D plane:

Ax=5cos30=5×32=53/2A_x = 5 \cos 30^\circ = 5 \times \frac{\sqrt{3}}{2} = 5\sqrt{3}/2
Ay=5sin30=5×12=5/2A_y = 5 \sin 30^\circ = 5 \times \frac{1}{2} = 5/2

Thus, the vector A\vec{A} in component form is:

A=532i^+52j^\vec{A} = \frac{5\sqrt{3}}{2} \hat{i} + \frac{5}{2} \hat{j}

5.2 Addition and Subtraction of Vectors

Vector Addition:

There are two main methods for adding vectors:

  1. Graphical Method (Head-to-Tail Rule): To add two vectors A\vec{A} and B\vec{B}, place the tail of vector B\vec{B} at the head of vector A\vec{A}, and the resultant vector R\vec{R} is drawn from the tail of A\vec{A} to the head of B\vec{B}.

  2. Algebraic Method (Component Form): If two vectors A=Axi^+Ayj^\vec{A} = A_x \hat{i} + A_y \hat{j} and B=Bxi^+Byj^\vec{B} = B_x \hat{i} + B_y \hat{j}, their sum is given by:

A+B=(Ax+Bx)i^+(Ay+By)j^\vec{A} + \vec{B} = (A_x + B_x) \hat{i} + (A_y + B_y) \hat{j}

In 3D, if A=Axi^+Ayj^+Azk^\vec{A} = A_x \hat{i} + A_y \hat{j} + A_z \hat{k} and B=Bxi^+Byj^+Bzk^\vec{B} = B_x \hat{i} + B_y \hat{j} + B_z \hat{k}, the sum is:

A+B=(Ax+Bx)i^+(Ay+By)j^+(Az+Bz)k^\vec{A} + \vec{B} = (A_x + B_x) \hat{i} + (A_y + B_y) \hat{j} + (A_z + B_z) \hat{k}

Example: Let A=3i^+4j^\vec{A} = 3\hat{i} + 4\hat{j} and B=2i^j^\vec{B} = 2\hat{i} - \hat{j}. The sum is:

A+B=(3+2)i^+(41)j^=5i^+3j^\vec{A} + \vec{B} = (3 + 2) \hat{i} + (4 - 1) \hat{j} = 5\hat{i} + 3\hat{j}
Vector Subtraction:

To subtract a vector B\vec{B} from A\vec{A}, we can use the following rule:

AB=A+(B)\vec{A} - \vec{B} = \vec{A} + (-\vec{B})

This means that we add A\vec{A} and the negative of B\vec{B}. The negative of a vector is obtained by reversing the direction of the vector (or multiplying it by 1-1).

If A=Axi^+Ayj^\vec{A} = A_x \hat{i} + A_y \hat{j} and B=Bxi^+Byj^\vec{B} = B_x \hat{i} + B_y \hat{j}, the difference is given by:

AB=(AxBx)i^+(AyBy)j^\vec{A} - \vec{B} = (A_x - B_x) \hat{i} + (A_y - B_y) \hat{j}

In 3D, if A=Axi^+Ayj^+Azk^\vec{A} = A_x \hat{i} + A_y \hat{j} + A_z \hat{k} and B=Bxi^+Byj^+Bzk^\vec{B} = B_x \hat{i} + B_y \hat{j} + B_z \hat{k}, the difference is:

AB=(AxBx)i^+(AyBy)j^+(AzBz)k^\vec{A} - \vec{B} = (A_x - B_x) \hat{i} + (A_y - B_y) \hat{j} + (A_z - B_z) \hat{k}

Example: Let A=3i^+4j^\vec{A} = 3\hat{i} + 4\hat{j} and B=2i^j^\vec{B} = 2\hat{i} - \hat{j}. The difference is:

AB=(32)i^+(4+1)j^=i^+5j^\vec{A} - \vec{B} = (3 - 2) \hat{i} + (4 + 1) \hat{j} = \hat{i} + 5\hat{j}

Summary of Key Concepts and Formulas:

  1. Definition of a Vector: A vector is represented by both magnitude and direction. Notation: A, B, or A\vec{A}.

  2. Rectangular Resolution:

    • In 2D, for a vector A\vec{A} making an angle θ\theta with the xx-axis: Ax=Acosθ,Ay=AsinθA_x = A \cos \theta, \quad A_y = A \sin \theta
    • In 3D, a vector A=Axi^+Ayj^+Azk^\vec{A} = A_x \hat{i} + A_y \hat{j} + A_z \hat{k}.
  3. Vector Addition:

    • Graphical: Head-to-tail method.
    • Algebraic: A+B=(Ax+Bx)i^+(Ay+By)j^\vec{A} + \vec{B} = (A_x + B_x) \hat{i} + (A_y + B_y) \hat{j}.
  4. Vector Subtraction:

    AB=(AxBx)i^+(AyBy)j^\vec{A} - \vec{B} = (A_x - B_x) \hat{i} + (A_y - B_y) \hat{j}
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