Steam Nozzles Notes

 Hello Everyone, Welcome to Rajasthan Polytechnic Blogs.

Subject - THERMAL ENGINEERING - II ME 4003
Branch - Mechanical Engineering
Semester - 4th Semester

📍⚡ Important 
👉 WhatsApp Group - Join Now
👉 Telegram Channel - Join Now

STEAM NOZZLES

A steam nozzle is a passage of varying cross-section through which steam flows to convert thermal energy into kinetic energy. Steam nozzles are commonly used in steam turbines, injectors, and other steam-powered devices where high-velocity steam is required.


4.1 Flow of Steam Through Nozzle

When steam enters a nozzle, it undergoes expansion due to a decrease in pressure. This expansion increases the velocity of the steam, converting heat energy into kinetic energy. The steam flow can be:

  • Subsonic Flow (Low velocity, before reaching the throat)

  • Sonic Flow (At the throat, when the velocity reaches the speed of sound)

  • Supersonic Flow (Beyond the throat, in a diverging section)

A nozzle can be of three types:

  1. Convergent Nozzle – Narrows down; increases velocity for subsonic flows.

  2. Divergent Nozzle – Expands; used for supersonic flows.

  3. Convergent-Divergent Nozzle – First narrows (throat), then expands; used in turbines.


4.2 Velocity of Steam at Exit of Nozzle (Using Heat Drop & Mollier Chart)

The velocity of steam at the exit of a nozzle can be calculated using the first law of thermodynamics (Steady Flow Energy Equation - SFEE):

V2=2(h1h2)V_2 = \sqrt{2(h_1 - h_2)}

Where:

  • V2V_2 = Exit velocity of steam (m/s)

  • h1h_1 = Enthalpy of steam at inlet (kJ/kg)

  • h2h_2 = Enthalpy of steam at exit (kJ/kg)

The heat drop (h₁ - h₂) can be determined from steam tables or the Mollier chart (h-s diagram).


4.3 Discharge of Steam Through Nozzles

The mass flow rate of steam through the nozzle is given by:

m=AVρm = A \cdot V \cdot \rho

Where:

  • mm = Mass flow rate (kg/s)

  • AA = Cross-sectional area (m²)

  • VV = Velocity of steam (m/s)

  • ρ\rho = Steam density (kg/m³)

At maximum discharge, steam reaches sonic velocity at the throat.


4.4 Critical Pressure Ratio

The critical pressure ratio (P₂/P₁) is the ratio of exit pressure (P2P_2) to inlet pressure (P1P_1) at which the mass flow rate is maximum. It is given by:

(P2P1)critical=(2n+1)nn1\left(\frac{P_2}{P_1}\right)_{\text{critical}} = \left(\frac{2}{n+1}\right)^{\frac{n}{n-1}}

Where:

  • nn = Expansion index (usually 1.3 for steam).

For steam, the approximate critical pressure ratio is 0.546 (i.e., the pressure at the throat is about 54.6% of inlet pressure for maximum discharge).


4.5 Calculation of Cross-Sectional Areas (Throat & Exit) for Maximum Discharge

To achieve maximum discharge, we calculate:

  1. Throat Area (Aₜ) – Minimum area where the steam velocity reaches sonic speed.

  2. Exit Area (Aₑ) – The final expanded area for maximum velocity.

The formula for throat area is:

At=mρtVtA_t = \frac{m}{\rho_t V_t}

Where:

  • ρt\rho_t = Density of steam at throat.

  • VtV_t = Velocity of steam at throat.

The exit area is calculated similarly using exit velocity and density.


4.6 Effect of Friction in Nozzles

  • Friction reduces kinetic energy by converting part of it into heat.

  • Due to friction, the actual velocity of steam is lower than the theoretical velocity.

  • The isentropic efficiency (η\eta) of the nozzle is given by:

η=Actual K.E. at exitTheoretical K.E. at exit\eta = \frac{\text{Actual K.E. at exit}}{\text{Theoretical K.E. at exit}}
  • Friction also increases steam entropy, affecting the enthalpy drop.


4.7 Super-Saturated Flow in Nozzles

  • In super-saturated flow, steam does not condense immediately even if it enters the wet region.

  • This happens when steam expands very quickly, preventing immediate droplet formation.

  • Effects of super-saturation:

    • Increases velocity beyond normal dry-saturated expansion.

    • Reduces heat drop because some energy remains in the vapor phase.

    • Can cause shock waves in the nozzle.


4.8 Working of a Steam Jet Injector

A steam jet injector (or ejector) is a device that uses high-velocity steam to pump water or another fluid.

Working Principle:

  1. High-pressure steam enters the injector and passes through a nozzle.

  2. This creates a high-velocity jet that generates suction, pulling in feedwater.

  3. The steam and water mix in a diffuser, where velocity decreases, and pressure increases.

  4. The resulting high-pressure mixture is delivered to the boiler.

Applications:

  • Used in boiler feed systems to pump water without mechanical parts.


4.9 Simple Numerical Problems

Example 1: Velocity at Nozzle Exit

Given:

  • Inlet enthalpy, h1=2800h_1 = 2800 kJ/kg

  • Exit enthalpy, h2=2500h_2 = 2500 kJ/kg

Find exit velocity (V2V_2):

V2=2×(h1h2)V_2 = \sqrt{2 \times (h_1 - h_2)} V2=2×(28002500)V_2 = \sqrt{2 \times (2800 - 2500)} V2=600V_2 = \sqrt{600} V2=34.64×10=346.4 m/sV_2 = 34.64 \times 10 = 346.4 \text{ m/s}

So, the exit velocity is 346.4 m/s.


Conclusion

  • Steam nozzles convert heat energy into kinetic energy, increasing steam velocity.

  • The critical pressure ratio ensures maximum mass flow rate.

  • Friction reduces efficiency, while super-saturation affects expansion behavior.

  • Steam jet injectors use high-velocity steam to pump fluids efficiently.

Post a Comment

0 Comments